Optimal. Leaf size=142 \[ \frac{2^{-m-1} \left (-4 m^3+390 m^2-8324 m+27783\right ) (2 x+1)^{1-m} \, _2F_1(1-m,-m;2-m;-3 (2 x+1))}{27 (1-m) m}-\frac{(3 x+2)^{m+1} \left (4 m^2-4 (109-2 m) m x-512 m+9261\right ) (2 x+1)^{-m}}{27 m}-\frac{2}{9} (5-4 x)^2 (3 x+2)^{m+1} (2 x+1)^{-m} \]
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Rubi [A] time = 0.176712, antiderivative size = 142, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.115, Rules used = {100, 146, 69} \[ \frac{2^{-m-1} \left (-4 m^3+390 m^2-8324 m+27783\right ) (2 x+1)^{1-m} \, _2F_1(1-m,-m;2-m;-3 (2 x+1))}{27 (1-m) m}-\frac{(3 x+2)^{m+1} \left (4 m^2-4 (109-2 m) m x-512 m+9261\right ) (2 x+1)^{-m}}{27 m}-\frac{2}{9} (5-4 x)^2 (3 x+2)^{m+1} (2 x+1)^{-m} \]
Antiderivative was successfully verified.
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Rule 100
Rule 146
Rule 69
Rubi steps
\begin{align*} \int (5-4 x)^3 (1+2 x)^{-1-m} (2+3 x)^m \, dx &=-\frac{2}{9} (5-4 x)^2 (1+2 x)^{-m} (2+3 x)^{1+m}+\frac{1}{18} \int (5-4 x) (1+2 x)^{-1-m} (2+3 x)^m (2 (223-10 m)-8 (109-2 m) x) \, dx\\ &=-\frac{2}{9} (5-4 x)^2 (1+2 x)^{-m} (2+3 x)^{1+m}-\frac{(1+2 x)^{-m} (2+3 x)^{1+m} \left (9261-512 m+4 m^2-4 (109-2 m) m x\right )}{27 m}+\frac{(288 (109-2 m) (1+m) (2+m)+6 (1+m) (-6 (-8 (223-10 m)-40 (109-2 m))-128 (109-2 m) m)+4 (180 (223-10 m)+12 (-8 (223-10 m)-40 (109-2 m)) m-128 (109-2 m) (1-m) m)) \int (1+2 x)^{-m} (2+3 x)^m \, dx}{432 m}\\ &=-\frac{2}{9} (5-4 x)^2 (1+2 x)^{-m} (2+3 x)^{1+m}-\frac{(1+2 x)^{-m} (2+3 x)^{1+m} \left (9261-512 m+4 m^2-4 (109-2 m) m x\right )}{27 m}+\frac{2^{-1-m} \left (27783-8324 m+390 m^2-4 m^3\right ) (1+2 x)^{1-m} \, _2F_1(1-m,-m;2-m;-3 (1+2 x))}{27 (1-m) m}\\ \end{align*}
Mathematica [A] time = 0.0871961, size = 106, normalized size = 0.75 \[ \frac{2^{-m-1} (2 x+1)^{-m} \left (\left (4 m^3-390 m^2+8324 m-27783\right ) (2 x+1) \, _2F_1(1-m,-m;2-m;-6 x-3)-(m-1) (6 x+4)^{m+1} \left (m^2 (8 x+4)+m \left (96 x^2-676 x-362\right )+9261\right )\right )}{27 (m-1) m} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.058, size = 0, normalized size = 0. \begin{align*} \int \left ( 5-4\,x \right ) ^{3} \left ( 1+2\,x \right ) ^{-1-m} \left ( 2+3\,x \right ) ^{m}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\int{\left (3 \, x + 2\right )}^{m}{\left (2 \, x + 1\right )}^{-m - 1}{\left (4 \, x - 5\right )}^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-{\left (64 \, x^{3} - 240 \, x^{2} + 300 \, x - 125\right )}{\left (3 \, x + 2\right )}^{m}{\left (2 \, x + 1\right )}^{-m - 1}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int -{\left (3 \, x + 2\right )}^{m}{\left (2 \, x + 1\right )}^{-m - 1}{\left (4 \, x - 5\right )}^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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